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雙語·從地球到月球 第四章 劍橋天文臺的回復

所屬教程:譯林版·從地球到月球

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2022年04月23日

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Barbicane, however, lost not one moment amid all the enthusiasm of which he had become the object. His first care was to reassemble his colleagues in the board-room of the Gun Club.There, after some discussion, it was agreed to consult the astronomers regarding the astronomical part of the enterprise.Their reply once ascertained, they could then discuss the mechanical means, and nothing should be wanting to ensure the success of this great experiment.

A note couched in precise terms, containing special interrogatories, was then drawn up and addressed to the Observatory of Cambridge in Massachusetts. This city, where the first university of the United States was founded, is justly celebrated for its astronomical staff.There are to be found assembled all the most eminent men of science.Here is to be seen at work that powerful telescope which enabled Bond to resolve the nebula of Andromeda, and Clarke to discover the satellite of Sirius.This celebrated institution fully justified on all points the confidence reposed in it by the Gun Club.

So, after two days, the reply so impatiently awaited was placed in the hands of President Barbicane. It was couched in the following terms:

The Director of the Cambridge Observatory to the President of the Gun Club at Baltimore.

CAMBRIDGE, October 7.

On the receipt of your favor of the 6th instant, addressed to the Observatory of Cambridge in the name of the members of the Baltimore Gun Club, our staff was immediately called together, and it was judged expedient to reply as follows:

The questions which have been proposed to it are these—

1.Is it possible to transmit a projectile up to the moon?

2.What is the exact distance which separates the earth from its satellite?

3.What will be the period of transit of the projectile when endowed with sufficient initial velocity?And, consequently, at what moment ought it to be discharged in order that it may touch the moon at a particular point?

4.At what precise moment will the moon present herself in the most favorable position to be reached by the projectile?

5.What point in the heavens ought the cannon to be aimed at which is intended to discharge the projectile?

6.What place will the moon occupy in the heavens at the moment of the projectile's departure?

Regarding the first question,“Is it possible to transmit a projectile up to the moon?”

Answer.—Yes;provided it possess an initial velocity of 12,000 yards per second;calculations prove that to be sufficient. In proportion as we recede from the earth the action of gravitation diminishes in the inverse ratio of the square of the distance;that is to say, at three times a given distance the action is nine times less.Consequently, the weight of a shot will decrease, and will become reduced to zero at the instant that the attraction of the moon exactly counterpoises that of the earth;that is to say at 47/52 of its passage.At that instant the projectile will have no weight whatever;and, if it passes that point, it will fall into the moon by the sole effect of the lunar attraction.The theoretical possibility of the experiment is therefore absolutely demonstrated;its success must depend upon the power of the engine employed.

As to the second question,“What is the exact distance which separates the earth from its satellite?”

Answer.—The moon does not describe a circle round the earth, but rather an ellipse, of which our earth occupies one of the foci;the consequence, therefore, is, that at certain times it approaches nearer to, and at others it recedes farther from, the earth;in astronomical language, it is at one time in apogee, at another in perigee. Now the difference between its greatest and its least distance is too considerable to be left out of consideration.In point of fact, in its apogee the moon is 247,552 miles, and in its perigee,218,657 miles only distant;a fact which makes a difference of 28,895 miles, or more than one-ninth of the entire distance.The perigee distance, therefore, is that which ought to serve as the basis of all calculations.

To the third question.

Answer.—If the shot should preserve continuously its initial velocity of 12,000 yards per second, it would require little more than nine hours to reach its destination;but, inasmuch as that initial velocity will be continually decreasing, it will occupy 300,000 seconds, that is 83hrs. 20m.in reaching the point where the attraction of the earth and moon will be in equilibrio.From this point it will fall into the moon in 50,000 seconds, or 13hrs.53m.20sec.It will be desirable, therefore, to discharge it 97hrs.13m.20sec.before the arrival of the moon at the point aimed at.

Regarding question four,“At what precise moment will the moon present herself in the most favorable position, etc.?”

Answer.—After what has been said above, it will be necessary, first of all, to choose the period when the moon will be in perigee, and also the moment when she will be crossing the zenith, which latter event will further diminish the entire distance by a length equal to the radius of the earth, i. e.3,919 miles;the result of which will be that the final passage remaining to be accomplished will be 214,976 miles.But although the moon passes her perigee every month, she does not reach the zenith always at exactly the same moment.She does not appear under these two conditions simultaneously, except at long intervals of time.It will be necessary, therefore, to wait for the moment when her passage in perigee shall coincide with that in the zenith.Now, by a fortunate circumstance, on the 4th of December in the ensuing year the moon will present these two conditions.At midnight she will be in perigee, that is, at her shortest distance form the earth, and at the same moment she will be crossing the zenith.

On the fifth question,“At what point in the heavens ought the cannon to be aimed?”

Answer.—The preceding remarks being admitted, the cannon ought to be pointed to the zenith of the place. Its fire, therefore, will be perpendicular to the plane of the horizon;and the projectile will soonest pass beyond the range of the terrestrial attraction.But, in order that the moon should reach the zenith of a given place, it is necessary that the place should not exceed in latitude the declination of the luminary;in other words, it must be comprised within the degrees 0°and 28°of lat.N.or S.In every other spot the fire must necessarily be oblique, which would seriously militate against the success of the experiment.

As to the sixth question,“What place will the moon occupy in the heavens at the moment of the projectile's departure?”

Answer.—At the moment when the projectile shall be discharged into space, the moon, which travels daily forward 13°10'35",will be distant from the zenith point by four times that quantity, i. e.by 52°42'20",a space which corresponds to the path which she will describe during the entire journey of the projectile.But, inasmuch as it is equally necessary to take into account the deviation which the rotary motion of the earth will impart to the shot, and as the shot cannot reach the moon until after a deviation equal to 16 radii of the earth, which, calculated upon the moon's orbit, are equal to about eleven degrees, it becomes necessary to add these eleven degrees to those which express the retardation of the moon just mentioned:that is to say, in round numbers, about sixty-four degrees.Consequently, at the moment of firing the visual radius applied to the moon will describe, with the vertical line of the place, an angle of sixty-four degrees.

These are our answers to the questions proposed to the Observatory of Cambridge by the members of the Gun Club:

To sum up—

1st. The cannon ought to be planted in a country situated between 0°and 28°of N.or S.lat.

2nd. It ought to be pointed directly toward the zenith of the place.

3rd. The projectile ought to be propelled with an initial velocity of 12,000 yards per second.

4th. It ought to be discharged at 10hrs.46m.40sec.of the 1st of December of the ensuing year.

5th. It will meet the moon four days after its discharge, precisely at midnight on the 4th of December, at the moment of its transit across the zenith.

The members of the Gun Club ought, therefore, without delay, to commence the works necessary for such an experiment, and to be prepared to set to work at the moment determined upon;for, if they should suffer this 4th of December to go by, they will not find the moon again under the same conditions of perigee and of zenith until eighteen years and eleven days afterward.

The staff of the Cambridge Observatory place themselves entirely at their disposal in respect of all questions of theoretical astronomy;and herewith add their congratulations to those of all the rest of America.

J. M.BELFAST,

Director of the Observatory of Cambridge.

不過,巴比凱恩并未因受到眾人的歡呼而忘乎所以。他首先要做的,是把他的同事們召集到大炮俱樂部的辦公室里來。在那兒,經過一番討論,大家同意就方案的天文學部分請教一下天文學家。等天文學家的回音一到,大家就將著手討論機械裝備的問題;而且,為保證這一偉大試驗的成功,任何細節(jié)都不可疏忽。

于是,一份包括一些專業(yè)問題的十分明確的紀要便擬好了,寄給了位于馬薩諸塞州的劍橋天文臺[15]。劍橋城是美國第一所大學的誕生地,而且也正是因為它的天文臺而享譽世界。那兒聚集著一些頂尖的科學家;那里的一臺高性能望遠鏡使邦德[16]解析了仙女座星云,使克拉克發(fā)現(xiàn)了天狼星。這座著名的天文臺完全值得大炮俱樂部信賴。

兩天后,大家焦急不安等待著的回信寄到了巴比凱恩主席的手中。內容如下:

劍橋天文臺臺長致巴爾的摩大炮俱樂部主席:

您本月六日以巴爾的摩大炮俱樂部全體會員的名義,寄給劍橋天文臺的信函,我臺業(yè)已收悉。我們立即開了會,并做出如下我們認為較為合適的答復。

您提出的問題歸納如下:

1.可不可能向月球發(fā)射一顆炮彈?

2.地球與它的這顆衛(wèi)星的精確距離是多少?

3.在給炮彈以足夠的初速度的情況下,它能飛行多長時間?而為了讓它落在月球上的某一個特定地點,應該何時發(fā)射為好?

4.炮彈落在月球上的最佳位置應該是在什么時候?

5.發(fā)射炮彈的大炮應該對準天空中的哪一個點?

6.炮彈射出時,月球將在天空中的什么位置?

就第一個問題:可不可能向月球發(fā)射一顆炮彈?現(xiàn)回答如下。

可以。如果能使炮彈的初速度達到每秒一萬二千碼的話,就可以向月球發(fā)射。經過計算,這一速度足夠了。隨著物體離開地球,地心引力的作用與距離的平方成反比,因而引力在逐漸減小,也就是說,如果距離變?yōu)樵瓉淼娜?,這一引力就將減小到原來的九分之一。因此,炮彈的重量在迅速減小,到月球的引力與地球的引力持平的時候,也就是說,在射程達到五十二分之四十七的時候,炮彈的重量就會減少到零。這時,炮彈就不再有重量了。如果它超越了這個點,它就將在唯一的月球的引力之下落在月球上。試驗的理論性完全得到了驗證。至于成功與否,那就只取決于發(fā)射裝置的功率了。

就第二個問題:地球與它的這顆衛(wèi)星的精確距離是多少?現(xiàn)回答如下。

月球圍繞地球運轉的軌跡并不是圓形的,而是橢圓形的,我們的地球占據著這個橢圓中心中的一個,因此,月球有時離地球較近,有時又較遠;用天文學術語來說就是,時而在遠地點,時而在近地點??墒?,最大距離與最小距離之間的差距是很大的,大到不容我們忽略。事實上,在遠地點時,月球距離地球二十四萬七千五百五十二英里;而在近地點時,距離則只有二十一萬八千六百五十七英里,相差兩萬八千八百九十五英里,超過總射程的九分之一。因此,近地點的距離應該作為考慮的基礎。

就第三個問題:在給炮彈以足夠的初速度的情況下,它能飛行多長時間?而為了讓它落在月球上的某一個特定地點,應該何時發(fā)射為好?現(xiàn)回答如下。

如果炮彈始終保持發(fā)射時的初速度——每秒一萬二千碼的話,它大約只需九個多小時便可到達目的地。但是,由于這個初速度將逐漸減小,經過推算,炮彈將要花費三十萬秒,亦即八十三小時二十分,才能到達地球引力和月球引力相抵消的點。然后,從這個點起,它將在五萬秒之后,亦即十三小時五十三分二十秒之后落到月球上。因此,應該在炮彈將到達月球上的那個瞄準點之前的九十七小時十三分二十秒之前發(fā)射它。

就第四個問題:炮彈落在月球的最佳位置應該是在什么時候?現(xiàn)回答如下。

根據剛才上面所說的,首先必須選擇月球在近地點的時刻,同時也要是它通過天頂[17]的時刻,這將能夠減少相當于一個地球半徑的距離,亦即三千九百一十九英里;這樣的話,最終射程則為二十一萬四千九百七十六英里。不過,如果說月球每月都經過近地點的話,那它并不是在這一時刻總是處在天頂。而這兩個條件同時具備的話,必須有一個很長的間隔。因此,必須等待月球到達近地點同時又在天頂?shù)臅r刻的到來。不過,巧得很,明年十二月四日,月球將正好具備這兩個條件:午夜時分,它將到達它的近地點,也就是說離地球最近的距離;與此同時,它又經過天頂。

就第五個問題:發(fā)射炮彈的大炮應該對準天空中的哪一個點?現(xiàn)回答如下。

根據上述看法,大炮應該瞄準天頂,這樣,炮彈飛出時與地平線呈垂直狀,它因此也就能盡快地擺脫地球引力。不過,要使這種情況出現(xiàn),即月球到達天空最高點的話,就必須讓這個地方的緯度不高于地球的赤緯[18],也就是說,它必須位于北緯或南緯的0°至28°之間。在其他任何地點,就必須傾斜發(fā)射,而這就可能影響試驗的成功。

就第六個問題:炮彈射出時,月球將在天空中的什么位置?現(xiàn)回答如下。

當炮彈將向天空發(fā)射時,每天以十三度十分三十五秒向前運行的月球,應該出現(xiàn)在離天頂是這個度數(shù)四倍距離的地方,亦即五十二度四十二分二十秒的地方,這一空間正好符合炮彈軌跡中月球的運行路線。不過,由于必須同時考慮到地球自轉所引發(fā)的炮彈的偏差,而且還由于炮彈只是經過一個相當于十六個地球半徑的偏差距離之后才到達月球(從月球軌道來看,這個偏差大約為十一度),因此,我們必須把這十一度加到所提及的月球離天空最高點的距離中去,變?yōu)榱亩日?。這樣一來,在發(fā)射炮彈時,月球視線方位將與發(fā)射點的垂直線構成一個六十四度的夾角。

這就是劍橋天文臺對大炮俱樂部的會員們提出的問題的回復。

概括起來,就是:

1.大炮必須安放在一個北緯或南緯0°至28°之間的地方。

2.大炮必須瞄準天空最高點。

3.炮彈的初速度必須達到每秒一萬二千碼。

4.炮彈應該在明年十二月一日晚上十點四十六分四十秒發(fā)射。

5.炮彈將于發(fā)射后的第四天,即精確時間十二月四日午夜時分,在通過天空最高點時到達月球。

因此,大炮俱樂部的會員們應該立即著手進行這樣的一次試驗所必需的工作,做好在規(guī)定時刻發(fā)射的準備;因為如果錯過了十二月四日這個日期的話,那就必須等到十八年零十一天以后,才能遇上月球同時符合既位于近地點又處在天空最高點的條件。

劍橋天文臺愿意毫無保留地回答所有有關天文學理論方面的問題,并與全國人民一起恭祝諸位馬到成功。

劍橋天文臺臺長

J. M.貝爾法斯特

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